(25x^2+5x-2)/25

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Solution for (25x^2+5x-2)/25 equation: 


x in (-oo:+oo)

(25*x^2+5*x-2)/25 = 0

25*x^2+5*x-2 = 0

25*x^2+5*x-2 = 0

DELTA = 5^2-(-2*4*25)

DELTA = 225

DELTA > 0

x = (225^(1/2)-5)/(2*25) or x = (-225^(1/2)-5)/(2*25)

x = 1/5 or x = -2/5

(x+2/5)*(x-1/5) = 0

((x+2/5)*(x-1/5))/25 = 0

( x+2/5 )

x+2/5 = 0 // - 2/5

x = -2/5

( x-1/5 )

x-1/5 = 0 // + 1/5

x = 1/5

x in { -2/5, 1/5 }

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